function
<cctype>
isspace
Check if character is a white-space
Checks whether c is a white-space character.
For the "C" locale, white-space characters are any of:
| ' ' | (0x20) | space (SPC) |
| '\t' | (0x09) | horizontal tab (TAB) |
| '\n' | (0x0a) | newline (LF) |
| '\v' | (0x0b) | vertical tab (VT) |
| '\f' | (0x0c) | feed (FF) |
| '\r' | (0x0d) | carriage return (CR) |
Other locales may consider a different selection of characters as white-spaces, but never a character that returns true for isalnum.
For a detailed chart on what the different ctype functions return for each character of the standard ASCII character set, see the reference for the <cctype> header.
In C++, a locale-specific template version of this function (isspace) exists in header <locale>.
Parameters
- c
- Character to be checked, casted to an int, or EOF.
Return Value
A value different from zero (i.e., true) if indeed c is a white-space character. Zero (i.e., false) otherwise.
Example
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/* isspace example */
#include <stdio.h>
#include <ctype.h>
int main ()
{
char c;
int i=0;
char str[]="Example sentence to test isspace\n";
while (str[i])
{
c=str[i];
if (isspace(c)) c='\n';
putchar (c);
i++;
}
return 0;
}
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This code prints out the C string character by character, replacing any white-space character by a newline character. Output:
Example
sentence
to
test
isspace
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See also
- isgraph
- Check if character has graphical representation (function)
- ispunct
- Check if character is a punctuation character (function)
- isalnum
- Check if character is alphanumeric (function)
- isspace (locale)
- Check if character is a white-space using locale (function template)