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Error in return type

philip1999 (36)
I want to count the number of numbers that are both divisible by 3 and 11 and wrote the following functions but it is showing an error.

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#include <iostream>

using namespace std;

int count1()
{
	int count = 0;
	for (int i = 0; i < 1001; i++)
	{
		if (i % 3 == 0)
		{
			count++;
		}
	}
	return count;
}

int count2()
{
	int count = 0;
	for (int i = 0; i < 1001; i++)
	{
		if (i % 11 == 0)
		{
			count++;
		}
	}
	return count;
}

int main()
{
	int total;

	total = count1 + count2;
	cout << total << endl;

	system("pause");
	return 0;
}
salem c (3700)
> total = count1 + count2;
Revise on how you call functions.

helios (17574)
That's not how you call functions.
total = count1() + count2();

However, your logic is incorrect. Can you spot the error?
Konstantin2 (142)
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int variant1(int from, int to) // [from, to)
{
	int cnt = 0;
	for (int i = from; i < to; i++)
		cnt += !(i % 3) && !(i % 11);
	return cnt;
}

int variant2(unsigned from, unsigned to) // [from, to)
{
	return ((to + 32) / 33) - ((from + 32) / 33);
}
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