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Dynamic memory - create multiple instances without explicitly call delete

graciano (66)
Hi,
Please look at this code:
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#include <iostream>
using namespace std;

class teste
{
public:
    teste(){x=33;};
    ~teste(){cout << x << endl;};
    int x;
};

int main()
{
    teste *x;
    for(int i=0;i<10;i++)
        x = new teste();
    return 0;
}


Each time i call "x = new teste();" the previous object is deleted?
Does this code cause any sort of memory leak?
Disch (13742)
Each time i call "x = new teste();" the previous object is deleted?


No. If you 'new' something, you have to 'delete' it or else it never gets cleaned up.

Every 'new' must have a matching 'delete'

Does this code cause any sort of memory leak?


Yes.
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