Email Address Validation

hi guys, i am wondering how to tackle this problem, please help.

***the most important thing is
no string, array or break is allowed for this programmme.

for the entry i may first input in a format like:
name <email>
e.g. june <[email protected]>

Rules are :
1. contain only one @
2. no consective dots

The output should be look like
name <email>
1 ok
2 ok
3 ok
4 ok
5 ok

or

name <email> (failed case)
1 ok
3 ok

can someone give me some clues?Thanks!!

Last edited on

Lowest0ne (1536)

If you cant use an array or string, then you need to calculate for each character:

This will print whatever you type in:

cout << "Please enter some things and then hit enter\n: ";

int ch;
while ((ch = cin.get()) != '\n')
  cout << ch;

So number 1:

cout << "Please enter some things and then hit enter\n: ";

int ch;
int atCount = 0; 
while ((ch = cin.get()) != '\n')
{
  switch(ch)
  {
  case '@':  ++atCount;  break;
  
  // Add the other important character events here
  }
}

if (atCount == 1) cout << "1 ok\n";

[/code]

Last edited on

OxBADC0DE (240)

He had better make use of an if...statement since the use of break is disallowed

eabc (3)

yes the three important things are no array no string and no break...

eabc (3)

can anyone help me?

SamuelAdams (1535)

I think they just did, if that is not clear, ask a question. Post your code so we can give comments

Last edited on

Lynx876 (742)

It says nothing about the use of continue;.

Use a for-loop, one iteration. When a 'rule' is broken continue; to restart the loop.

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Email Address Validation