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2D Array

death1239 (2)
Hello, i want to add a function that determines whether in the component of the matrix A exists a magic square of dimension k >= 2, that is, the sums of the elements on the rows, columns, and diagonals of the square are equal; if so, the screen will display YES and the coordinates of the left-top corner and the size k of the square found, otherwise the message NO will be displayed. How can i implement thhis?
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#include <iostream>
#include <fstream>
#include <conio.h>
#include <string.h>
#include <windows.h>
#include <bits/stdc++.h>
#include <vector>

using namespace std;

 int n,m;
 int A[50][50];

 ifstream in("Lacusta.in");
 ofstream out("Lacusta.out", ios::app);

 
void read(){ //reading the data from file
if (!in.is_open())
    cout<<"Error opening file";

    in>>n>>m;
    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < m; j++)
        {
          in >> A[i][j];
        }
    }

}

void display(){ //matrix data display
 cout<<endl;
 for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < m; j++)
        {
            cout << A[i][j] << "\t";
        }
        cout<<endl;
    }

}



void addrow(){  //inserting a new row
    int temp[50][50];
    n++;
    cout<<endl;

    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < m; j++)
        {
            if(i==0){
            cout<<"["<<i<<"]["<<j<<"]=";
            cin>>temp[i][j];
            }
            else temp[i][j] = A[i-1][j];
        }
    }

    for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < m; j++)
        {
           A[i][j]=temp[i][j];
        }
    }

}

int main()
{
read();
    cout<< "[1] - Display the matrix "<<endl;
    cout<< "[2] - Input a new row"<<endl;
char a;
do{
    cout<<"\nInput option:  ";
    a = getch();
    switch(a){
        case '0': break;
        case '1':
        display(); 
        break;
        case '2':
        addrow(); 
        break;
        default: cout<< "\n \t~ INEXISTENT ~ \n"; getch();
        }
}while(a!='0');


return 0;
}



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Lacusta.in Data :
4 5
3 4 5 7 9
6 6 3 4 4
6 3 3 9 6
6 5 3 8 2

newbieg (764)
Here's how geeksforgeeks would do it:
https://www.geeksforgeeks.org/check-given-matrix-is-magic-square-or-not/?ref=lbp
Next step might be to utilize vector<vector <int> > matrix2d; and double check that the number of rows matches number of columns at the top of the function (not sure why gfg doesn't bother with that).
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