terminate called after throwing an instance of 'long'
I am getting this error when I try to run my code. Since it doesn't give any lines that this error occur, I really don't know what to do.
Here is my code:
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#include <iostream>
#include "Hash.h"
#include <algorithm>
#include <string>
Hash::Hash(unsigned int size) {
arr = new Node[size];
sz = size;
cur_pt = 0;
}
unsigned int Hash::hasher(string key) {
if (key.size() == 0) {
throw(NULL);
}
unsigned int retval = 0;
for (int i = 0; i < key.size(); ++i) {
retval += key[i];
}
return retval % sz;
}
bool Hash::empty() {
if (cur_pt == 0) {
return 1;
}
return 0;
}
bool Hash::insert(string key, double value) {
if (cur_pt == sz) {
return 0;
}
int index = hasher(key);
Node n;
n.key = key;
n.value = value;
if (arr[index].key != "") {
throw(NULL);
}
arr[index] = n;
cur_pt++;
}
bool Hash::remove(string key) {
int index = hasher(key);
if (arr[index].key == key) {
arr[index] = Node();
cur_pt--;
return 1;
}
return 0;
}
double Hash::find(string key) {
for (int i = 0; i < sz; ++i) {
if (key == arr[i].key) {
return arr[i].value;
}
}
return -1;
}
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Last edited on
The only places you throw is on line 14 and 39 so it's probably one of those lines. A debugger can tell you exactly.
If you don't know about debuggers, you can insert a line like
cout << "line 14\n"; in that points;
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