also for your particular case, since 30 degrees is equal to π/6, this is something I got shown and had to memorize in trig, the 30-60-90 triangle:
https://qph.fs.quoracdn.net/main-qimg-c7979fa834b089bf2065db2bee5ac7a1
using SOHCAHTOA , an acronym to help remember,
- sin is "opposite"/hypotenuse
- cos is "adjacent"/hypotenuse
- tan is "opposite"/"adjacent"
(in degrees)
sin(0) = 0
sin(30) = 1/2
sin(60) = √3/2
sin(90) = 1
sin(120) = √3/2
sin(150) = 1/2
sin(180) = 0
If you can imagine a cartesian plane, look at top-right quadrant (quadrant I) and draw an angle of 30 degrees and form a triangle exactly like linked. To visualize higher angles like 120, from the positive x axis you'd continue counter-clockwise over into quadrant II
https://www.onlinemathlearning.com/image-files/quadrants.png . iirc you'd draw a triangle touching the negative x axis, so really you'd see sin(120) is same as sin(60), but in quadrant II. The sides of that 30-60-90 triangle are -1, √3, and 2, but for sin(60) purposes, the -1 is not involved, so it's still √3/2
Similarly, sin(150) is like sin(30) in quadrant II. You'd draw a triangle like this
https://qph.fs.quoracdn.net/main-qimg-27511e6d248c21e1c2d68f39a61d13d1 and visually you can see it's still positive 1/2.